Question

Find the sum of the first 16 positive Integers divisible by 6.​

Answer 1

Answer: 816 is the sum of 16 positive integers that are divisible by 06.

Step-by-step explanation: The first 16 positive integers that are divisible by 6 are 6,12,18,24,etc

we have to find We need to find

$S_{n = \frac{n}{2} [2a +(n-1)d]$

$S_{16} = \frac{16}{2}[2(6)+(16-1)6]$

$=8[12+15(6)]$

= $8(12+90)$

= $8(102)$

= $816$