find the sum of the first 20 terms of an A.P whose common different is 3 times of its first term and its 5th term is 26
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Step-by-step explanation:
t5=a+4d=26
d=3a
a+4*3a =26
13a = 26
a=2
d=6
sum of 20 terms = 20/2 *(2*2+[20-1]6)
sum of 20 terms = 1180
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