Question

find the sum of the first 22 terms is an AP whose d=7, and 22nd term is 149​

Answer 1

Answer:

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Step-by-step explanation:

Given d = 7,

22nd term = 149 ,

⇒ a+21d = 149

⇒a+21(7) = 149

⇒a+147 = 149

⇒a=149-147=2

Sn = (n/2)(2a+(n-1)d)

S₂₂ = (22/2)(2×2+(22-1)7)

S₂₂ = 11(4+21(7))

S₂₂ = 11(4+147)

S₂₂ = 11(151)

S₂₂ = 1661.

Answer 2

Answer:

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