find the sum of the first 24 term of the list of who's nth term is given by an =3+2n
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let n be 1,2,3,4....
then placing the value of 1,2,3,4... on n u will get AP
let n=1
therefore an = 3+2(1)=5
likewise do
then a=5
d=2
then use sn formula
Sn=n/2(2a+(n-1)d)
= 24/2[10+23(2)]
= 12[10+46]
= 12(56)
= 672
hope this answer is right and hope it may help u
then placing the value of 1,2,3,4... on n u will get AP
let n=1
therefore an = 3+2(1)=5
likewise do
then a=5
d=2
then use sn formula
Sn=n/2(2a+(n-1)d)
= 24/2[10+23(2)]
= 12[10+46]
= 12(56)
= 672
hope this answer is right and hope it may help u
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