Find the sum of the first 25 odd natural numbers.
Answers
Answered by
1
Step-by-step explanation:
a=1 d=2
S25= n/2(2a+(n-1)d)
=> S25= 25/2 (24)2 = 25×24
=> 600
Answered by
19
Answer:
Answer is 625
The number series 1,3,5,7,9 .... ,49 .
Therefore, 625 is the sum of first 25 odd numbers .
Step 1:- Address the formula , in put parameters and values .
Input parameters and values :
The number series 1,3,5,7,9 .... ,49 .
The first term a=1
The common difference d=2
Total numbers of terms n=25
Step 2:- Apply the input parameter values in the AP formula .
Sum = n/2×(a+Tn)
= 25/2×(1+49)
= (25×50)/2
= 1250/2
= 1+3+5+7+9 .... +49=625
Therefore, 625 is the sum of first 25 odd numbers .
Step-by-step explanation:
hope it will help you
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