find the sum of the first 25 term of an AP whose nth term is given by an=3n+7
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Answer:
25=Ap
an=3n+7
i) 3x x7=21
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Find the sum of first 25 term of an AP whose n term is given by SN=7-3n?
We have, Sn = 7 - 3n
Putting n = 1
Then, S1 = 7 - 3 × 1 = 4
Now , putting n = 2
Then, S2 = 7 - 3 × 2 = 1
So , a = 4 and d = T2 - T1 = 1 - 4 = -3
Now , we have to find the sum of first 25th term of A.P.
Using , Sn = n/2 [ 2a + ( n - 1 ) d ]
S25 = 25/2 [ 2 × 4 + ( 25 - 1 ) - 3 ]
= 25/2 [ 8 + 24 × ( - 3 ) ]
= 25/2 [ 8 - 72 ]
= 25/2 × ( - 64 )
= 25 × ( - 32 )
= - 800
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