Math, asked by pavan963015, 3 months ago


Find the sum of the first 30 positive integers divisible by 6.​

Answers

Answered by llawlliet
30

The number series 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, .. ..., 180.

First term (a) = 6

Common difference (d)= 6

Number of terms (n) = 30

Last term (l) = 180

 =  n \div 2 \times a  + l \\  = 30 \div 2 \times 6 + 180 \\  = 30 \times 186 \div 2 \\  = 5580 \div 2 \\   = 270

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