find the sum of the first 40 positive integer divisible by 6
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Step-by-step explanation:
The positive integers divisible by 6 are 6,12,18,.......
This is an example of A.P. (Arithmetic progression).
Sum of n terms of an A.P. is given by,
Sn=n/2×[2a+(n-1)d]
where,
a=first term =6
d=common difference=6
Thus,
Sn = 40/2×{2(6)+(39)6}
=20{12+234}
=20×246
=4920
Hence The Answer is 4920
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