Question

Tan(alpha + beta) is equals to root 3
Tan(alpha-beta) is equal to 1 then tan 6 beta is.......

Answer 1

Answer:

Step-by-step explanation: here's your solution

Answer 2

Answer:

The answer is $1$.

Step-by-step explanation:

It is given that :

$tan (\alpha +\beta ) = \sqrt{3} \\tan (\alpha +\beta )=tan 60^{0} (\sqrt{3}=tan 60^{0} ) \\\alpha +\beta =60^{0}$  ---- Let this be (i)

Also, $tan (\alpha -\beta )=1$

$tan (\alpha -\beta )=tan 45^{0} (tan 45^{0} = 1)\\\alpha -\beta = 45^{0}$----- Let this be (ii)

From (i) and (ii), we get that :

$-2\beta =-15^{0} \\\beta =15^{0} /2\\\\tan 6\beta = (15^{0} /2) * 6\\= tan 45^{0} \\= 1$

Hence the answer is 1.