Question

Find the sum of the first 40 positive integers divisible by 6.​

Answer 1

Answer:

let a= 6 and let d= 6 n= 40

S40 = 40/2(2x6 + 39x6)

=20(12+234)

= 20(246)

=4920

hope this answer helps!!

mark me the brainliest!!

Answer 2

Answer:

it's easy yaa

Step-by-step explanation:

from given

a=6

d=6

n=40 and

we must find Sn

for finding it we must apply an formula

Sn = n/2(2a+(n-1) d)

by substituting the values

S40=40/2(2×6+(40-1)×6)

S40=20(12+49×6)

S40=20(12+234)

S40=20×246

S40=4920

hope u understand..

follow me mark as brainlest answer....