Question

find the sum of the first 40 positive integers divisible by 6.​

Answer 1

Step-by-step explanation:

there are two image first is of first side and the second one is the second side.☝️☝️☝️☝️☝️

Answer 2

Answer:

Have a nice day..

Step-by-step explanation:

Here,

we have to find the sum of the first 40 positive integers divisible by 6.

Now,

the first no. is (a) = 6

then

$a \ \frac{}{40} = 6 + 39 \times 6$

$= 240$

Therefore,

sum of the numbers...

$s\frac{}{40} = \frac{40}{2} \times (2 \times 6 + 39 \times 6)$

$= 4920$

so,

the sum of the first 40 positive integers divisible by 6. are 4920.

thanks a lot...