Question

Please help me with this math​

Answer 1

Answer:

GIVES THAT :–

$a + b = \sqrt{3} \: \: and \: \: a - b = \sqrt{2}$

TO FIND :–

Value of ab( a² + b² )

=》BY GIVEN EQUATION –

$a = \frac{ \sqrt{3} + \sqrt{2} }{2} \: \: and \: \: b = \frac{ \sqrt{3} - \sqrt{2} }{2}$

• ab = 1/4
• a² + b² = 10/4

SO THAT –

$ab( {a}^{2} + {b}^{2} ) = \frac{1}{4} ( \frac{10}{4} ) = \frac{5}{8}$

#FOLLOW ME...

Answer 2

❥${\purple{\underline{\underline{\large{\mathtt{ANSWER:-}}}}}}$

Value of ab(a²+b²) is 5/8.

❥${\purple{\underline{\underline{\large{\mathtt{EXPLANATION:-}}}}}}$

• Given:-

• a+b = √3
• a-b = √2

•To find:-

• Value of ab(a²+b²).

•Solution:-

Taking a+b = √3

† Squaring in both sides,†

→(a+b)² = (√3)²

→(a-b)² +4ab = 3

† Putting the value of a-b=√2 †

→(√2)² +4ab = 3

→2 + 4ab = 3

→4ab = 1

→ ab =1/4

★ Now find the value of ab(a²+b²)★

ab(a²+b²)

= ab (a+b)²-2ab

† Putting all values †

= 1/4(√3)²-2×1/4

=5/8