find the sum of the first 40 positive integers divisible by 5
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5, 10,15,20.................200(40terms)
5+10..............+200
5(1+2+3+4+...........40)
5(n(n+1)/2) (n=40)
5(40(40+1)/2)
5(20)(41)
4100 is ur answer
5+10..............+200
5(1+2+3+4+...........40)
5(n(n+1)/2) (n=40)
5(40(40+1)/2)
5(20)(41)
4100 is ur answer
Answered by
0
Answer:
4100 is the answer .......
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