Find the sum of the first 40 terms of the arithmetic sequence 3/4,1/4,-1/4,-3/4,-5/4
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Yeah this can be done using few formulas of arithmetic progressions
First of all
First term (a) = 3/4
Common difference (d) = -2/4 = -1/2
n = 40
Sum of an A.P = (2a + (n-1)d)/2
= (3*2/4 + (40-1)(-1/2))/2
=(3/2 - 39/2)/2
= (-36/2)/2
=-36/4
= -9
Thus sum of first 40 terms is -9
Hope it helps, Please mark as brainliest:)
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