Find the sum of the following AP's (i) 5,7,9,11,...to 18terms
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a=5 ,d=2 ,n=18
18th term = a+17d = 5+17(2)
i.e. 18th term or last term is 39
now,
sum of terms = n/2(first term + last term)
i.e. 18/2(5+39)
9(44)= 396
answer is 396
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