Find the sum of the following APs. 2.0 12...to 10 terms (n) (
Answers
Answered by
1
Answer:
Solution:-
2,□,26
Let the missing term be x.
As we know, in an A.P., the difference between two consecutive terms is equal.
∴x−2=26−x
⇒x+x=26+2
⇒2x=28
⇒x=
2
28
=1
Answered by
2
2,7,12…10 terms
a=2,d=5,n=10
S
n
=
2
n
[2a+(n−1)d]
S
10
=
2
10
[4+9(5)]=245
ii)
0.6,1.7,2.8… 100 terms.
a=0.6,d=1.1,n=100
S
100
=
2
100
[2(0.6)+99(1.1)]=5505
Some thanks
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