Question

Find the sum of the following APs(ii) -37, -33, -29, …… to 12 terms​

Answer 1

Answer:

a = -37

d = + 4

Sn = n/2 (2a +(n-1)d)

S12 = 12/2 (2(-37)+(11)(4))

S12 = 6(-74+44)

S12 = 6(-30)

S12 = - 180

thus the sum of 12 terms is - 180

Answer 2

here a is -37

d is -4

a12=a+(n-1)d

-37+(12-1)-4

-37+(11)-4

-37-44

=-81

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