find the sum of the following GP
√3+3 + 3√3+
...... to 10 terms
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Answer:Sn=a[r^n-1]/(r-1)
S10=v3 [v3 ^10-1]/v3 - 1
=v3 [243-1]/(v3 - 1)=242v3 /(v3 - 1)=121v3(v3+1)
=121[ 3+v3]
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