find the sum of the following series 1+4+9+16+...+225
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Answered by
50
the series is 1²+2²+3²+4²+........+15²
by using formula
1²+2²+..........+n² = n(n+1)(2n+1)/6
where n= 15
so, sum of series is
15(15+1)(2×15+1)/6
= 15×16×31/6
= 5×8×31
=40×31 = 1240
i hope it will be helpful for u
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4
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