Question

two cells of 30V and and 6V with internal og 6ohm and 9ohm respectively are connected as shown . find the current in each branch and potential difference across the cells using Kirchoff's law​

Answer 1

Answer:

=

r

1

E

1

+

r

2

E

2

r

eff

=

r

1

+r

2

r

1

r

2

=

3+2

(3)(2)

=6/5Ω

6/5

E

eff

=

3

6

+

2

4

6

5

E

eff

=2+2=4

E

eff

=

5

24

I=

5

6

+8

5

24

=

5

46

5

24

=

46

24

I

8

=

46

24

×84

=

23

96

V