Question

find the sum of the given ap
а) 34+32+30+--------------+10​

Answer 1

Answer:

Step-by-step explanation:

a=34,

d=32−34=−2

a  

n

​

=10

or, a+(n−1)d=10

or, 34+(n−1)(−2)=10

or, −2(n−1)=−24

or, n−1=12

⇒n=13

∴S  

13

​

=  

2

13

​

[2(34)+12(−2)]

=  

2

13

​

×2[34−12]

=13×22=286.