Question

Find the sum of the integers between 100 and 200 that are (1) divisible by 9. (2) not divisible by9
(int (): These numbers will be: Total numbers - Total numbers divisible by 9)​

Answer 1

Step-by-step explanation:

108,117,126,........198

a=108,d=9,an=198

an=a+(n-1)d

198=108+(n-1)9

198=108+9n-9

198=99+9n

99=9n

n =11

now put sn formula and find the numbers the answer will be 1083