Find the sum of the integers between 100 and 500 that are divisible by 9
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Answer:
Step-by-step explanation:
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Step-by-step explanation:
AP= 108,117,.....,495
a=108, d=9
an=a+(n-1)d
495= 108+(n-1)9
387=9(n-1)
387=9n-9
n=44
Sn= n/2[2a+(n-1)d]
=44/2[2x108+(44-1)x9]
=22[216+387]
Sn= 13266
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