Question

find the sum of the lengths of the base of a Trapezium whose altitude is 14 cm and area is 105 CM square ​

Answer 1

Answer:

the answer is 15cm

Step-by-step explanation:

Area od trapezium=1/2× SUM of ll sides× height

105= 1/2×sum of parallel sides × 14cm

sum of parallel sides= 105/7cm

= 15cm

hope it will help

Answer 2

☆ CORRECT QUESTION :

Q] Find the sum of lengths of the parallel sides of a trapezium whose altitude is 14 cm and area is 105 cm^2.

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Sum\:of\:parallel\:sides=15cm}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given :}} \\ \implies \text{Length \: of \: altitude = 14 \: cm} \\ \\ \implies \text{Area \: of \: trapezium = 105} \: cm^{2} \\ \\ \red{ \underline \bold{To \: Find :}} \\ \implies \text{Sum \: of \: length \: of \: parallel \: sides = ?}$

• In the given question information given about a trapezium whose altitude and area is given that is 14 cm and 105 cm^2 and we have to find the sum of its parallel sides.

• So, first we apply the formula of area of trapezium that is half times sum of parallel sides times altitude.

• Consider sum of parallel sides be (a+b).

• According to given question :

$\implies \text{Area \: of \: trapezium} = \frac{1}{2} \times (sum \: of \: parallel \: sides) \times altitude \\ \\ \pink{\text{Putting \: the \: given \: values}} \\ \implies 105 = \frac{1}{2} \times (a + b) \times 14 \\ \\ \implies 105 \times 2 = (a + b) \times 14 \\ \\ \implies 210 = (a + b) \times 14 \\ \\ \implies (a + b) = \frac{210}{14} \\ \\ \green{\implies \text{(a + b) = 15 \: cm}}$