find the sum of the lengths of the bases of a trapezium whose area is 4.2 m2 and whose height is 280 cm
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Area of a trapezium is 1/2(a+b)h,
where, a and b are the parallel sides,and
h is perpendicular height.
So, if we divide the area(4.2*100*100=42000) by height,
we get 1/2 of the sum of a and b.
42000/280= 150.
Sum of parallel sides = 150*2=300cm=3m.
1.5m*2.8m=4.2 Sq. Meter.
where, a and b are the parallel sides,and
h is perpendicular height.
So, if we divide the area(4.2*100*100=42000) by height,
we get 1/2 of the sum of a and b.
42000/280= 150.
Sum of parallel sides = 150*2=300cm=3m.
1.5m*2.8m=4.2 Sq. Meter.
vidhyavarshan:
thank u very mucj
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36
your ans is in this pic
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