find the sum of the lengths of the bases of a trapezium whose
altitude is 17 cm and whose area is 0.85 m2:
Answers
Answered by
4
Answer:
area=0.85m2. altitude=17cm=0.17m Sum of the lengths of the bases=2×area/altitude=2×0.85/0.17=
Answered by
0
Area=0.85m², altitude=17cm=0.17m
Sum of the lengths of the bases = 2×0.85/0.17=10m
Hope it helps..!!
Similar questions