Find the sum of the 'n' terms of the series 1+3)(1+3+5) +.......
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Answered by
1
Answer:
13
Step-by-step explanation:
Answered by
2
Answer:
(1+3)+(1+3+5)+.......
an=1+3+5+.....2(n+1)-1
=(n+1)(1+2(n+1)-1)/2
=(n+1)^2
=n^2+2n+1
sum to n terms
sum of k^2+2k+1
n(n+1)(2n+1)/6+2n(n+1)/2+n
n/6(2n^2+9n+13)
Step-by-step explanation:
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