Question

find the sum of the remainders when the polynomial
P(X)=x3-3x2+4x-9 is divided b
by (x-1) and (x+2)​

Answer 1

Answer:

G(X) = X-1

X = 1.

P(X) = X³-3X²+4X-9

P(1) = (1)³ - 3 × (1)² + 4 × 1 -9

= 1 - 3 + 4 - 9 = 5 - 12 = -7

Again,

G(X) = (X+2)

X = -2

P(X) = X³-3X²+4X -9

P(-2) = (-2)³ -3 × (-2)² + 4 × -2 -9

= -8 -3 × 4 -8 -9

= -8-12-17 = -37

Therefore,

Sum of the remainders = (-7) + (-37) = -7 -37 = -44

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Answer 2

Answer:

2x3-16

Step-by-step explanation:

x3-3x2+4x-9/(x-1)(x+2)

x3-3x2+4x-9/X2+2x-x-2

x3-3x2+4x-9/X2+x-2

x3-8/2x3-16