Find the sum of the series (2^3 - 1)+(4^3 -3^3)+(6^3-15^3)+... to (i) n terms (ii) 8 terms
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Answer:
your answer will be -3115.
Step-by-step explanation:
(8-1)+(64-27)+(216-3375)
7+37-3159
=-3115
hope it helps you
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