Find the sum of the series 5+7+9+11+13.... Upto 40 terms
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2
here
first term a=5
last term l=83
d=2
n=40
n/2(a+l)=1760
first term a=5
last term l=83
d=2
n=40
n/2(a+l)=1760
Answered by
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#Hey mate#
a=5
d=2
n=40
Sol:
Sn=n/2[2a+(n-1)d]
=40/2[2×5+(40-1)2]
=20[10+39×2]
=20[10+78]
=20×88
Sn=1760
#$amu#
a=5
d=2
n=40
Sol:
Sn=n/2[2a+(n-1)d]
=40/2[2×5+(40-1)2]
=20[10+39×2]
=20[10+78]
=20×88
Sn=1760
#$amu#
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