Find the sum of the series
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rahul200013:
yep i get it
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Answer:
Step-by-step explanation:
S = 0.3+0.33+0.333+……n terms.
Now taking 3 common from the sum we have ,
S = 3 x [0.1+0.11+0.111+…. n terms]
Now to further simplify , we can multiply and divide by 9,
S = 3/9 x [0.9+0.99+0.999+…..n terms]
We can also write this as,
S = 3/9 x [(1–0.1)+(1–0.01)+(1–0.001)+……n terms]
Summing up all the 1’s, it becomes n times ,
S = 1/3 x [n - (0.1 + 0.01 + 0.001 +….. n terms)]
Applying the G.P formula ,
S = 1/3 x (n – 0.1[1 - (0.1)^n]/1 – 0.1)
S = 1/3 x (9n – {1 – [0.1]^n}/9)
Hope This Helps You
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