find the sum of the series3+7+11 ------- to 10 terms
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Answer:
a = 3
d = 7-3 = 4
n = 10
Sn = (n/2) 2a+(n-1)d
S10 = (10/2 2(3) + (10-1)4
S10 = 5 (6+(9)4)
S10 = 5 (6+36)
S10 = 210
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