Question

find the sum of the square of first 11 natural numbers​

Answer 1

Step-by-step explanation:

Sum of squares of first 11 natural numbers

n ( n + 1 ) ( 2n + 1 )

S = ------------------------

6

11 ( 11 + 1 ) ( 22 + 1 )

= ------------------------

6

11 (12) (23)

= --------------

6

= 506

Answer 2

Given,

The first 11 natural numbers​

To find,

The sum of the square of the first 11 natural numbers​.

Solution,

We can simply solve this mathematical problem by using the subsequent mathematical operation

The formula for finding the sum of the squared of natural numbers is as follows :

Σn² = [n(n+1)(2n+1)] / 6

Where ‘n’ represents Natural number

Here, n = 11

Σ11²  = [11(11+1)(2*11+1)] / 6

Σ11²   = [11(12)(23)] /6

Σ11²  = (3036) / 6

Σ11²  = 506

Hence, the sum of the square of first 11 natural numbers is 506