Find the sum of
The sum of first 45 natural numbers is____
Pls answer the above question if u know.
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As you know the first 45 natural number is
1.2.3.4.5.6.7.8.9.10.11.12.13.14.15.16.17.18.19.20.21.22.23.24.25.26.27.28.29.30.31.32.33.34.35.36.37.38.39.40.41.42.43.44.45.
So, their sum are 1035
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Answer:
1+2+3+....+45,here first term a=1 last term 1=45, total number of terms n=45,so the sum s=n/2{a+l}=45/2{1+45}=45*25=1035
s=n(n+1)/45(45+)/2=45*23=1035
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