Question

find the sum of the terms of an A.P 2.6,0,114...32

Answer 1

brother!! first of all! it's not an AP!so please!ask a sensible ques

Answer 2

Answer:

hey the question is wrong as 32 can't be the term as we add 4 consecutively we will get 18,22,26,30,34 see there's no 32

and if you meant that 32 is the number of term than 

s=n/2(2a+(n-1)*d)

32/2(4+31*4)

16*(128)

2^4*2^7*(for easier calculation)

=2^11

2048

Read more on Brainly.in - https://brainly.in/question/67201#readmoretep-by-step explanation:

a = 2, d = 6 - 2 = 4, n = 32 Sum of n terms = sn = n/2[2a+(n-1)d] Substituting = 32/2[2(2)+(32-1)4] = 16[4+(31)4] = 16[4+124] = 16 * 128 = 2048 Hence Sum of terms of AP 2,6,10,14..........,32. is 2048

Read more on Brainly.in - https://brainly.in/question/67201#readmore