Math, asked by Aswin9895, 1 year ago

Find the sum of the two digit numbers divisible by 6

Answers

Answered by jahnavipriya23
0

Answer:

810

Step-by-step explanation:

the AP will be 12, 18,24........................96 [ since the first 2-digit number divisible by 6 is 12 and last is 96]

a=12 , d=6, an=96

an= a+[n-1] d

96= 12 + [ n-1] 6

[n-1]6 = 96-12

[n-1]6 = 84

n-1= 84/6

n-1= 14

n=15

Sn = n/2[a +an]

S15= 15/2[12+96]

S15= 15/2[108]

S15=810

therefore, sum of all two digits numbers divisible by 6 is 810

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