Find the sum of the two digit numbers divisible by 6
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Answer:
810
Step-by-step explanation:
the AP will be 12, 18,24........................96 [ since the first 2-digit number divisible by 6 is 12 and last is 96]
a=12 , d=6, an=96
an= a+[n-1] d
96= 12 + [ n-1] 6
[n-1]6 = 96-12
[n-1]6 = 84
n-1= 84/6
n-1= 14
n=15
Sn = n/2[a +an]
S15= 15/2[12+96]
S15= 15/2[108]
S15=810
therefore, sum of all two digits numbers divisible by 6 is 810
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