Question

Find the sum of the zeroes of the polynomial y2+9y+20.

Answer 1

Hey! Here's your answer! y^2 + 9y + 20 = 0 y^2 + 4y + 5y +20 = 0 y(y + 4) + 5(y + 4) = 0 (y + 4)(y + 5) = 0 y = -4 or -5 -4 and -5 are zeroes of tje polynomial. - 4 + (-5) = -9 Hope this helps! :)

Answer 2

Answer:

-9

Step-by-step explanation:

y²+4y+5y+20=0

ANS== 0