Question

find the sum of the zeros of a quadratic polynomial is 15 upon 4
and their product is 3. find the Polynomial.​

Answer 1

Answer:

Step-by-step explanation:

Method 1:

The quadratic equation with sum of roots and product of roots given will be of form x² - (sum of roots)x + product of roots

Given, Sum of zeroes = 15/4,  Product of zeroes = 3

=> x² - 15/4 * x + 3

=> 4x² - 15x + 12

Method 2:

Let the polynomial be of form p(x) = ax² + bx + c

Sum of zeros = 15/4

=> -b/a = 15/4

Assuming a = 1

b = -15/4.

Product of zeros = 3

=> c/a = 3

assuming a = 1,

c = 3.

Thus the equation of polynomial with a= 1, b = -15/4, c = 3 is  

p(x) = (1)x² + (-15/4) * x + 3

     = x² - 15x/4 + 3

     = 4x² - 15x + 12

Answer 2

Answer:

k[4x²-15+12]

Step-by-step explanation:

Go through the above image,

hope it helps!!