Find the sum of three digit numbers divisible by both 3and 4
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Answer:
41400
Step-by-step explanation:
The numbers divisible by 3 and 4 will be divisible by 12.
So the required three digit numbers are 108, 120, 132, ___, 996.
No of terms = (996-108)/12 + 1 = 75
Sum = 75/2 * (108+996) = 41400
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