find the sum of two middle most integers of the A.P -4/3, -1 , -2/3 , ..... ..... 13/3.
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a = -4/3
a2 = -1
a3 = -2/3
an = 13/3
d = -1 + (4/3) = 1/3
an = a + (n - 1)d
(13/3) = (-4/3) + (n - 1)*(1/3)
13 = -4 + (n - 1)
n - 1 = 13 + 4 = 17
n = 18
Middle two terms of the A.P are a9 & a10.
a9 = a + 8d = (-4/3) + 8*(1/3) = 4/3
a10 = a + 9d = (-4/3) + 9*(1/3) = 5/3
a9 + a10 = 4/3 + 5/3 = 9/3 = 3 ——> Answer
a2 = -1
a3 = -2/3
an = 13/3
d = -1 + (4/3) = 1/3
an = a + (n - 1)d
(13/3) = (-4/3) + (n - 1)*(1/3)
13 = -4 + (n - 1)
n - 1 = 13 + 4 = 17
n = 18
Middle two terms of the A.P are a9 & a10.
a9 = a + 8d = (-4/3) + 8*(1/3) = 4/3
a10 = a + 9d = (-4/3) + 9*(1/3) = 5/3
a9 + a10 = 4/3 + 5/3 = 9/3 = 3 ——> Answer
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