Question

find the sum of two middle most teram of the Ap -4/3,-1,-2/3_____,4.1/3​

Answer 1

Answer:

Sn of first AP/ Sn of second AP=n/2(2a+(n-1)d)/n/2(2a’ (n-1)d’)=(n+1)/2n+4 = 2a+(n-1)d/2a’+(n-1)d’=n+1/2n+4 For M1=8 Taking n=2m1-1=16-1=15, we get 2a+14d/2a’+14d’=16-1+1/32-2+4 2a+14d/2a’+14d’=16/34 Dividing by 2 a+7d/a’+7d’=8/17(ratio of first 8 terms) For M2=n, Taking n=2m2-1 where m=n, we get 2a+(2n-2)d/2a’+(2n-2)d’=2n/4n+2 Dividing by 2 =a+(n-1)d/a’+(n-1)d’=2n/4n+2 =a+(n-1)d/a’+(n-1)d’=n/2n+1

Step-by-step explanation:

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