Question

The two ends of a train moving with constant acceleration pass a certain point with velocities u and 3u. The velocity with which the middle point of the train passes the same point is

Answer 1

Answer:

From the third kinematical equation,

9u^2 - u^2 = 2*a*(length of train)

Therefore,

Length of train = 4u^2/a

So, the length passed till the middle point of train reaches the point of observation = 2u^2/a

So,

v^2 - u^2 = 2*(2u^2/a)*a

So,

v^2 = 5u^2 So, v = √5u

This is the velocity and the answer.

Answer 2

Answer:

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