Question

Find the sum of zeroes of the polynomial 4x2 + 16x +8.

Answer 1

Answer:

-4

Step-by-step explanation:

sum of roots = -b/a

b=16

a=4

SOR=-b/a= -16/4 = -4

Answer 2

Answer:

$\large \alpha+ \beta =-4$

$\large \alpha\times\beta=4$

Step-by-step explanation:

Given :

$\large p(x)=4x^2 + 16x +8$

We have to find sum and product of zeroes.

We know for sum of zeroes = - b / a

where b is  coefficient of x term and a is  coefficient of x² term .

$\large p(x)=4x^2 + 16x +8\\\\\\\large \alpha+ \beta =-\dfrac{16}{4}\\\\\\\large \alpha+ \beta =-4$

Now for product we have c / a

where c is constant term and  a is  coefficient of x² term .

$\large p(x)=4x^2 + 16x +8\\\\\\\large \alpha\times\beta=\dfrac{8}{2}\\\\\\\large \alpha\times\beta=4$

Thus we get answer.