Find the sum of zeroes of the polynomial
p (x)=x2+7x+10.
Answers
Answered by
5
LET suppose,
p(x)=x²+7x+10
zeros of the polynomial is actually the value of x where p(X) =0
put p(x)=0
0=x²+7x+10
or x²+7x+10=0
now we can easily find out the roots of above equation by splitting middle terms
so that,
x²+5x+2x+10=0
x(x+5)+2(x+5)=0
x+2=0,
x+5=0
so that x=-2
and x=-5
so the value of x is either -2 or -5
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Answered by
5
Answer:
sum of zeros=-7
Step-by-step explanation:
p(x)=x2+7x+10
x2+7x+10=0
splitting it
x2+5x+2x+10=0
x(x+5)+2(x+5)=0
(x+2)(x+5)=0
x+2=0 x+5=0
x=-2 x=-5
alpha=-2 beta=-5
sum of zeros=-2+(-5)=-7
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