Math, asked by saicharan1886, 9 months ago

Find the sum on which the difference between the simple interest and the compound interest at the rate of 8% per annum compounded annually be rupee 64 in 2 years.

Answers

Answered by deenagadhi
6

Step-by-step explanation:

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Answered by PADMINI
10

Given :

Rate = 8%

Time = 2 years

Difference= 64

To Find :

The Sum.

Solution:

Let \: sum \: be \: Rs \: x

Simple Interest (SI) :

 =  >  \dfrac{x \times 8 \times 2}{100}

 =  >  \dfrac{4x}{25}  = 0.16x

Compound Interest (CI):

For First Year:

 =  >  \dfrac{x \times 8 \times 1}{100}  = 0.08x

 = > 0.08x + 1 = 1.08x

For Second Year:

 =  >  \dfrac{1.08x \times 8 \times 1}{100}  = 0.864x

Total Compound Interest :

 =  > 0.08x + 0.0864x

 =  > 0.1664x

The difference between the simple interest and the compound interest at the rate of 8% per annum compounded annually be 64 in 2 years.

Finding the Sum :

Simple Interest - Compound Interest = 64

 =  >  0.16x - 0.1664x = 64

 =  > 0.0064x = 64

 =  > x =  \dfrac{0.0064}{64}

 =  > x = 10000

Hence, the sum is Rs 10,000

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