Question

Find the sum to infinity of the sequence \\(128, 64, 32,…\\)

Answer 1

Given : infinity of the sequence  128 , 64 , 32 ..........

To find : Sum

Solution:

128  , 64  , 32  , ........................

First term a  = 128

Common Ratio = 64/128  =  1/2

Sum of infinite series  = a/(1 - r)

= 128/(1 - 1/2)

= 128/(1/2)

= 256

sum to infinity of the sequence  128  , 64  , 32  , ........................ = 256

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