Find the sum to n terms of the series
1/ 1*2 + 1 / 2*3 + 1/ 3*4 + .............
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I think it could be 1
Vikas8935:
Tn = nth term of the series = 1/(n)(n+1) = (n+1-n)/(n)(n+1) = 1/n - 1/(n+1)If you add all the terms of this series (to n terms), you get a sum of 1 - 1/(n+1) as all the other terms cancel out.So sum of 9 terms = 1 - 1/10 = 9/10.
Thanks Vikas
welcome jahnvi
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