Find the sum to n terms of the series whose n^th term is n(n+3)
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n(n+3)=n=10=10(10+3)=100+30=130
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Answer:
n(n+1)(n+5)/3
Step-by-step explanation:
n(n+3) multiply n inside
then put ∑
and distribute it
∑n²+3∑n
n(n+1)(2n+1)/6+3(n)(n+1)/2
simplify and get the answer
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