Find the sum to nth terms 1-2+3-4+5-6+...
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S(n) = 1 - 2 + 3 - 4 + 5 - 6 .... n terms
S(n=1) = 1 S(2) = -1 S(3) = 2
S(4) = -2 S(5)= 3 S(6) = -3
S(2k - 1) = k S(2k)= - k k= 1,2,3 ....
S(n) = (n+1)/2 if n is odd
= - n/2 if n is even.
S(n=1) = 1 S(2) = -1 S(3) = 2
S(4) = -2 S(5)= 3 S(6) = -3
S(2k - 1) = k S(2k)= - k k= 1,2,3 ....
S(n) = (n+1)/2 if n is odd
= - n/2 if n is even.
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