Question

:) Find the sum upto n terms of the GP.
x3, x5, x7​

Answer 1

Step-by-step explanation:

Given Find the sum upto n terms of the GP.

• x3, x5, x7
• We know that Sn = a(1 – r^n) / 1 – r
• Here first term a = x^3
• So common ratio r = x^5 / x^3
•                              = x^2
• Therefore sum to n terms = a(1 – r^n) / 1 – r
• So a = x^3 and r = x^2
• Sn = x^3 (1 – (x^2)^n) / 1 – x^2
•     = x^3 (1 – x^2n) / 1 – x^2

So sum of n terms is x^3(1 – x^2n) / 1 – x^2

Reference link will be

https://brainly.in/question/5879495